A train 156 m long passes a km stone in 30 seconds and another train of the same length travelling in opposite direction in 10 seconds. The speed of the second train is
Length of train = 156 m and time taken = 30 seconds
=> Speed of first train = $$\frac{156}{30}=5.2$$ m/s
Let speed of second train (length = 156 m) = $$x$$ m/s
According to ques, => $$(x+5.2)=\frac{156+156}{10}$$
=> $$(x+5.2)=31.2$$
=> $$x=31.2-5.2=26$$ m/s
$$\therefore$$ Speed of second train = $$26\times(\frac{18}{5})=93.6$$ km/hr
=> Ans - (A)
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