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Question 117
A hemispherical bowl has internal radius of 6 cm. The internal surface area would be: $$(take\ \pi -3.14)$$
Solution
Radius of bowl = 6 cm
Surface area of hemisphere = $$3\pi r^2$$
= $$2\times3.14\times(6)^2$$
= $$2\times113.04=226.08$$ $$cm^2$$
=> Ans - (D)
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