Question 119

If water is freezed to become ice, its volume is increased by 10%, then if the ice is melted to water again, its volume will be decreased by:

Solution

Let initial volume of water = $$10$$ $$cm^3$$

Increase in volume = 10%

=> Volume of ice = $$10\times\frac{(110)}{100}=11$$ $$cm^3$$

If the ice is melted to water again, its volume will be decreased by = $$\frac{(11-10)}{11}\times100$$

= $$\frac{100}{11}=9\frac{1}{11}\%$$

=> Ans - (D)

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