Question 119
If water is freezed to become ice, its volume is increased by 10%, then if the ice is melted to water again, its volume will be decreased by:
Solution
Let initial volume of water = $$10$$ $$cm^3$$
Increase in volume = 10%
=> Volume of ice = $$10\times\frac{(110)}{100}=11$$ $$cm^3$$
If the ice is melted to water again, its volume will be decreased by = $$\frac{(11-10)}{11}\times100$$
= $$\frac{100}{11}=9\frac{1}{11}\%$$
=> Ans - (D)
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