If A is 50% more than B. B is how much percent less than A?
Let $$B = 10$$
=> $$A=10+(\frac{50}{100}\times10)=10+5=15$$
=> Required % = $$\frac{(15-10)}{15}\times100$$
= $$\frac{100}{3}=33.33\%$$
=> Ans - (D)
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