Question 116

If the six-digit number 479 xyz is exactly divisible by 7, 11 and 13, then $$\left\{(y + z) \div x\right\}$$ is equal to:

Solution

Given that six-digit number$$ 479 xyz$$

written as 479479 then $$x=4,y=7,z=9$$

then $$\left\{(y + z) \div x\right\}$$

put the value

$$\left\{(7+ 9) \div 4\right\}$$

$$\Rightarrow \dfrac{9+7}{4}$$

$$\Rightarrow \dfrac{16}{4}$$

$$\Rightarrow 4 $$Ans

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