Question 116
Divide 27 into two parts so that 5 times the first and 11 times the second together equals to 195. Then ratio of the first and second parts is
Solution
Let the two parts be $$x$$, $$27-x$$
According to the Problem
$$5x+11\left(27-x\right)=195$$
$$=$$> $$5x+297-11x=195$$
$$=$$> $$6x=297-195$$
$$=$$> $$x=17$$
$$\therefore$$Required ratio$$=x:(27-x)=17:(27-10)=17:10$$
Hence, the correct answer is Option A
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