IF $$z = x + iy$$, where $$i = (-1)$$, then
I. $$z = 0, when x = 0, y$$ ≠ $$20$$
II. $$If a + bi = c + di, then a = c, b = d$$

Solution

It is given that $$z = x + iy$$, where $$i = (-1)$$

If $$x=0$$, then $$z=iy$$

Hence, first statement is not true.

II : $$If a + bi = c + di, then a = c, b = d$$

If an equation contains both real and imaginary numbers, then the real numbers are equal, and the coefficient of imaginary numbers are also equal.

Hence, second statement is true.

=> Ans - (B)

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IF $$z = x + iy$$, where $$i = (-1)$$, thenI. $$z = 0, when x = 0, y$$ ≠ $$20$$II. $$If a + bi = c + di, then a = c, b = d$$