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Each question below has two statements, I and II. Mark your answer as:
Question 114
If $$y = 2x$$, then
I. $$\sin y = \frac{2 \tan x}{1 + \tan^2 x}$$
II. $$\cos y = \frac{2 \tan x}{1 - \tan^2 x}$$
Solution
$$sin(2\theta)=\frac{2 tan\theta}{1+tan^2\theta}$$
and $$cos(2\theta)=\frac{1- tan^2\theta}{1+tan^2\theta}$$
Thus, if $$y=2x$$, then only first statement is true.
=> Ans - (A)
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