In $$\triangle ABC, \angle B = 90^{\circ}$$ and $$AB : BC = 1 : 2$$. The value of $$\cos A + \tan C$$ is:

A

$$\frac{5 + \sqrt{2}}{2\sqrt{5}}$$

B

$$\frac{1 + \sqrt{5}}{2\sqrt{5}}$$

C

$$\frac{2\sqrt{5}}{2 + \sqrt{5}}$$

D

$$\frac{2 + \sqrt{}}{2\sqrt{5}}$$