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For $$x \neq -1$$, define $$\frac{x - 1}{x + 2}$$, then $$f(x) = \frac{f(x) - f(y)}{1+f(x)f(y)}$$
$$\frac{x+y}{1-xy}$$
$$\frac{x-y}{1+xy}$$
$$\frac{x+y}{x-y}$$
1
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