Solution
As we can see there difference of the sequence is in arithmatic progression of difference 1
Second term = first term + 4
Third term = second term + 5
Fourth term = third term + 6
nth term = (n-1)th term + (4 + (n-1)*1)
Adding above equation we get
nth term = first term + (4+5+6....+(3+(n-1)))
hence 6th term will be 32.
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