Solution
$${(a+b+c)^2}$$ = $$a^2 + b^2 +c^2 + 2(ab +bc +ac)$$
48 = 16 + 2(ab+bc+ac)
32 = 2(ab+bc+ac)
ab+bc+ac=16......(1)
as $$a^2 + b^2 + c^2$$ = 16......(2)
using 1 and 2
a=b=c
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