Question 110
x is directly proportional to 4 more than the square of y. x is 39 when y is 3. What is the value of $$\sqrt{y}$$ when x is 60?
Solution
As per the question (assuming the proportionality quotient be 'k'): x = k($$y^2$$+4)
Substituting the given values, 39 = k(9+4), which makes k as 3.
Now, the value of $$\sqrt{\ y}$$ when x is 60: 60 = 3($$y^2$$+4)
From the above equation, $$y^2$$ = 16, which makes y as 4 and the square root of y as 2.
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