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Question 11
If a man cycles at 10 km/hr, then he arrives at a certain place at 1 p.m. If he cycles at 15 km/hr, he will arrive at the same place at 11 a.m. At what sped must he cycle to get there at noon?
Solution
Let the distance to be travelled be D.
In the first case, D/10 = t
In the second case, D/15 = t-2
=> D/15 = D/10 - 2
=> 2D = 3D - 60
=> D = 60 km and T = 6 hours
Therefore, to get there at noon, he has to travel at 60/5 = 12 km/hr
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