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Question 11
C is the mid-point of PQ, if P is (4, x), C is (y, -1) and Q is (-2, 4), then x and y respectively are
Solution
Midpoint of P(x1,y1) , Q(x2,y2) = C($$\frac{x1+x2}{2},\ \frac{y1+y2}{2}$$)
So $$y=\frac{4-2}{2},\ -1=\ \frac{x+4}{2}$$
On solving x=-6 and y=1
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