The sides of $$\triangle ABC$$ are 10 cm, 10.5 cm and 14.5 cm. Whatis the radius of its circumcircle?
The $$\triangle$$ ABC is a right angled triangle because
$$(14.5)^2=(10)^2+(10.5)^2=210.25$$
Also, circumradius of a right triangle is half of hypotenuse = $$\frac{14.5}{2}=7.25$$ cm
=> Ans - (D)
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