Question 106
If the perimeter of a rectangle is 138 metres and the difference between the length and breadth is 7 metres, what is the area of the rectangle ?
Solution
Let the length be x and breadth be y.
x - y = 7
The perimeter of rectangle is 138
2x + 2y = 138
x + y = 69
2x = 76
x = 38
y = 31
Area of rectangle = 31*38 = 1178
Option D is correct.
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