If $$\frac{sec\theta+tan\theta}{sec\theta-tan\theta}=\frac{5}{3}$$, then $$ sin\theta $$ is equal to :
$$\frac{sec\theta+tan\theta}{sec\theta-tan\theta}=\frac{5}{3}$$
$$3sec\theta + 3tan\theta$$ = $$5sec\theta - 5tan\theta$$
$$2sec\theta$$ = $$8tan\theta$$
$$sin\theta$$ = $$\frac{1}{4}$$
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