Question 106

ABCD is a cyclic quadrilateral in which AB = 15 cm, BC = 12 cm and CD = 10 cm. If AC bisects BD, then what is the measure of AD?

Solution

Given ABCD is a cyclic quadrilateral where AB=15,BC= 12,CD =10

is given below diagram

from the above diagram AC bisects BD

$$\triangle is similar \triangle BCD

$$ \frac{AB}{AD} = \frac{DC}{BC} $$

$$\Rightarrow \frac{15}{AD} = \frac{10}{12}$$

$$\Rightarrow AD = \frac{15\times 12} {10} $$

$$\Rightarrow AD = 18 cm

therefore Option (C) 18 cm Ans

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