A is 20% more efficient than B. If B alone can complete a piece of work in 12 days, then A alone can complete the same work in how many days?
Let B's efficiency = 1 unit/day
=> Total work to be done = $$1\times12=12$$ units
A is 20% more efficient than B, => A's efficiency = $$1\times\frac{120}{100}=1.2$$ units/day
$$\therefore$$ Time taken by A working alone = $$\frac{12}{1.2}=10$$ days
=> Ans - (A)
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