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Question 106
A, B and C together can complete a work in 20 days. A and B together can complete the same work in 30 days. Then C alone can complete the same work in how many days?
Solution
Work done by C alone = $$\frac{1}{20}-\frac{1}{30}$$
= $$\frac{3-2}{60}=\frac{1}{60}$$
$$\therefore$$ Time taken by C alone = $$\frac{1}{\frac{1}{60}}=60$$ days
=> Ans - (D)
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