Question 103

The simplest value of
$$\frac{1}{\sqrt{2} + \sqrt{3}} + \frac{1}{\sqrt{3} + \sqrt{4}} + \frac{1}{\sqrt{4} + \sqrt{5}} + \frac{1}{\sqrt{5} + \sqrt{6}}$$

Solution

after rationalizing each term in question, it will be: $$\sqrt{6} - \sqrt{2}$$
or $$\sqrt{6} - \sqrt{2}$$
 = $$\sqrt{2}(\sqrt{3}-1)$$


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