A man travels for 5 hours 15 minutes. If he covers the first half of the journey at 60 km/h and rest at 45 km/h. Find the total distance traveled by him

Let total distance travelled = $$2d$$ km and total time taken = 5 hr 15 min = $$5\frac{1}{4}$$ hrs

Half of the distance (i.e. $$d$$ km) is travelled at $$60$$ km/hr and remaining at $$45$$ km/hr

Using, time = distance/speed

=> $$(\frac{d}{60})+(\frac{d}{45})=5\frac{1}{4}$$

=> $$\frac{d}{15}(\frac{1}{4}+\frac{1}{3})=\frac{21}{4}$$

=> $$\frac{d}{15}\times(\frac{7}{12})=\frac{21}{4}$$

=> $$d=\frac{21}{4}\times\frac{12}{7}\times15$$

=> $$d=9\times15=135$$

$$\therefore$$ Total distance travelled = $$2\times135=270$$ km

=> Ans - (C)