we need to calculate square root of $$(\frac{\sqrt{3} + \sqrt{2}}{\sqrt{3} - \sqrt{2}})$$
let $$(\frac{\sqrt{3} + \sqrt{2}}{\sqrt{3} - \sqrt{2}})$$ be = y
on rationalizing y , we get
y = $$(\surd2 + \surd3)^2$$
hence square root of y => $$\surd(y)$$ = $$\surd2 + \surd3$$
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