A person distributes his pens among four friends A, B. C, D in the ratio 1/3 : 1/4 : 1/5 : 1/6 .What is the minimum number of pens that the person should have?
It is given that A person distributes his pens among four friends A, B. C, D in the ratio 1/3 : 1/4 : 1/5 : 1/6
LCM of 3,4,5,6 is 60.
A:B:C:D = 60/3 : 60/4 : 60/5 : 60/6
= 20+15+12+10
Hence the minimum 57 pens should be there with the man before distribution.
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