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Question 101

A and B can do a piece of work in 20 days.The same work can be done by B and C in 30 days; C and A in 40 days. If A works alone the numberof days required to complete the work is

Solution

Let the work capacity of A,B,C be a,b,c units/day respectively.
Let the amount of work be 120 units

Hence, we can frame the following equations:
a+b = 6
b+c = 4
a+c = 3
Adding up all these 3, we get: a+b+c = 6.5
From this, we can say that a = 2.5

Hence, the time required by A alone to get work done = 120/2.5 = 48 days

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