Question 10

In the adjoining figure, three equal squares are placed. The squares are unit squares The area of the shaded region in $$(incm^2)$$ is

image

Solution

Place the lower left square on coordinates from $$(0,0)$$ to $$(1,1)$$. The two slanted boundaries of the shaded triangle have equations $$y=2-2x$$ and $$y=\frac{x}{2}$$, so they intersect at $$\left(\frac{4}{5},\frac{2}{5}\right)$$. The shaded triangle has a vertical base of length $$2$$ and horizontal height $$\frac{4}{5}$$. Its area is $$\frac{1}{2}\cdot2\cdot\frac{4}{5}=\frac{4}{5}$$.

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