Question 10

If $$(3^{33} + 3^{33} + 3^{33})(2^{33} + 2^{33}) = 6^x$$, then what is the value of x?

Solution

$$(3^{33} + 3^{33} + 3^{33})(2^{33} + 2^{33}) = 6^x$$
$$(3*3^{33})(2*2^{33}) = 6^x$$
$$(3^{34})(2^{34})=6^x$$
$$6^{34}=6^x$$
x=34

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