If another store 'F' sold number of multigrain packets which is average number of multigrain packets sold by stores 'C', 'D' and 'E' and average number of whole-wheat packets sold by stores 'A' and 'E'. If store 'B' sold each packet at ₹ 240 and store 'F' sold each packet at 20% more than that of 'B', then total revenue collected by store 'F' is.

Number of multigrain packets sold by store C, D and E = 72, 54 and 84 respectively.

Number of whole wheat packets sold by store A and E = 44 and 72 respectively.

So, number of multigrain packets sold by store F = $$\dfrac{72+54+84}{3}=70$$

Number of whole wheat packets sold by store F = $$\dfrac{44+72}{2}=\dfrac{116}{2}=58$$

So, total number of packets sold by store F = $$70+58=128$$

Selling Price of each packet of store F = ₹ $$240\times\ 1.2=288$$

So, total revenue collected by store F = ₹ $$288\times\ 128$$ = ₹ $$36864$$

So, option B is the correct answer.