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Find the smallest 8 digit number which is exactly divisible by 121.
Smallest 8 digit number = 10000000
If we divide above number by 121, remainder is = $$10000000 = 121\times82644+76$$
=> Smallest 8 digit number which is exactly divisible by 121 = $$10000000+(121-76)=10000045$$
=> Ans - (A)
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