Consider two point masses $$m_1$$ and $$m_2$$ connected by a light rigid rod of length $$r_0$$. The moment of inertia of the system about an axis passing through their centre of mass and perpendicular to the rigid rod is given by

A

$$\frac{m_1 m_2}{2(m_1 + m_2)} r_0^2$$

B

$$\frac{m_1 m_2}{m_1 + m_2} r_0^2$$

C

$$\frac{2 m_1 m_2}{m_1 + m_2} r_0^2$$

D

$$\frac{m_1^2 + m_2^2}{m_1 + m_2} r_0^2$$