XAT Charts Questions

Total number of Physics major from all locations = 225

$$\therefore $$ Total number of students = $$\frac{225}{0.18}$$ = 1250

Number of students majoring in chemistry = 14 % * 1250 = 175

Hence, option B.

Total number of Physics major from all locations = 225

$$\therefore $$ Total number of students = $$\frac{225}{0.18}$$ = 1250

Number of engineering students = 20% * 1250 = 250

So, basis the given condition we have

$$\frac{18}{225}$$=$$\frac{x}{250}$$

=> x = 20

Hence, option D

(Note: This question has been presented as was in the actual paper and has been solved by the aid of visual inference)

Total number of Physics major from all locations = 225

$$\therefore $$ Total number of students = $$\frac{225}{0.18}$$ = 1250

Students from Chennai = 12% * 1250 = 150

Given, number of Physics majors from chennai = 40

$$\therefore $$ maximum possible number of economic students from chennai = 150 - 40 = 110

Maximum percentage of students = $$\frac{110}{150}$$ * 100 % = 73.33 %

Hence, option A.

Let the required percentage be P.

Option A: PA = (6.5 - 4) * 100/ 4 = 62.5%

Option B: PB = (8 - 5) * 100/ 5 = 60%

Option C: PC = (7 - 4) * 100/ 4 = 75%

Option D: PD = (9 - 5.5) * 100/ 5.5 = 63.63%

Thus, option C shows the maximum year-on-year growth and is the answer.

Prof. Arithmetic: There are two such instances, during 2013-14 and 2015-16

Prof. Algebra: There are three such instances, during 2011-12, 2014-15 and 2015-16

Prof. Geometry: There are two such instances, during 2010-11 and 2013-14

Prof. Calculus: There are two such instances, during 2010-11 and 2014-15

Thus, there are 2+3+2+2 = 9 such instances.

Hence, option C is the answer.

Research efficiency = (total number of publications)/(total time spent in research)

Prof. Arithmetic: RE = (8) / [90*(0.7 + 0.5 + 0.6)] = 8 / (18 * 9)

Prof. Algebra: RE = (8) / [90*(0.3 + 0.4 + 0.25)] = 8 / (9.5 * 9)

Prof. Geometry: RE = (8) / [90*(0.75 + 0.25 + 2)] = 8 / (12 * 9)

Prof. Calculus: RE = (8) / [90*(0.55 + 0.55 + 0.4)] = 8 / (15 * 9)

Thus, we can observe that Prof. Arithmetic has the lowest efficiency.

Hence, option A is the answer.

Let's tabulate the information given in the graph, 

For a salary range we can get the highest and the lowest value of the range but cannot get the distribution of individual student. 

In the year 2008 we have a complete salary range(76-100) inside it and some students of the range 51-75. 

In the year 2009 some students of the range 51-75 and some students of the range 75-100. 

In the year 2010 some students of the range 51-75 and some students of the range 75-100. 

In the year 2012 we have a complete salary range 51-75 inside it and some students of the range (76-100) . 

Since we cannot determine the exact students and cannot infer a particular year, Hence answer is E i.e cannot be determined.

Let's tabulate the information given in the graph, 

In all the options since 2009 is given 

Lets check if 2009 is satisfying the given criteria 

Median salary of 2009 = 24 l 

Avg salary of 2008 = 16 l

So Median salary of 2009 is between 40 to 50% higher than 2008 avg salary.

Hence options 1,3,4,5 can be negated . 

Option B is the correct answer

Let's tabulate the information given in the graph, 

The number of years cannot be calculated with precision as the distribution pattern is unknown .

Hence E is the correct answer

Let's tabulate the information given in the graph, 

It is clear from the table that the  mean salary after discarding the unemployed students is greater than the mean salary for the years 2008,2010,2013

Hence A is the correct answer.

After the USA, we have to find a country with the highest spending on the Military as a % of GDP.

From the chart for Military Expenditure, it can be easily seen that the bar graph for India is higher than any other country except the USA.

Hence, option C is the answer.

This change can be observed by viewing the chart.

Where all other countries saw a gradual drop in their “industry as a % of GDP”, for Malaysia in 2008-09, the fall was sudden and had the maximum value among the options.

Hence, option D is the answer.

From the chart for “services, value-added as a % of GDP” we can see that every other country, except India, has a constant value or decrease from 2000-10, whereas India shows a slow but gradual increase.

Hence, option B is the answer.

We are not aware that which year, out of the given year is 2010. Hence, we can say that the data is insufficient. Therefore, option E is the best suitable answer. 

The revenue of Yahoo in 4th year = 250 millions.

The revenue of Yahoo in 6th year = 1200 millions.

Therefore, average percentage increase in Yahoo's revenue in a year = $$[(\dfrac{1200}{250})^{0.5}-1]*100$$ = 119%

The revenue of Facebook in year 4 = 300 millions

The revenue of Facebook in year 6 = 2000 millions

Therefore, average percentage increase in Facebook's revenue in a year = $$[(\dfrac{2000}{300})^{0.5}-1]*100$$ = 159%

Therefore, the required difference = 159 - 119 = 40%. Hence, option B is the correct answer.

Google’s percentage growth in revenues from the fifth to the sixth year = $$\dfrac{3200-1500}{1500}\times 100$$ = 113.33 percent. 

Therefore, Facebook's revenue in the 6th year = $$\dfrac{100+113.33}{100}\times 750$$ = 1600 millions. 

Therefore, option A is the correct answer.

Total runs scored in 4's = $$\dfrac{43.16}{100}\times 306$$ = 132 

Therefore, total number of 4's scored by the batsman = $$\dfrac{132}{4}$$ = 33

Total runs scored in 6's = $$\dfrac{3.92}{100}\times 306$$ = 12 

Therefore, total number of 6's scored by the batsman = $$\dfrac{12}{6}$$ = 2

Hence, we can say that option E is the correct answer. 

Net increment in the number of runs due to 5 the dot balls resulting in 4s and two 3s resulting in two 1s = 4*5 - 2*2 = 16.

Therefore, the total number of runs scored by the batsman = 16 + 306 = 322 runs.

The number of runs scored by 4's = 132 + 20 = 152        {We know that batsman scored 132 runs from 4s alone}

The angle subtended by 4's = $$\dfrac{152}{322}\times 360$$ = 169.93 $$\approx$$ 170.

Total value of assets in the year 2004 = 100 crore

Total value of sales in the year 2004 = 0.60*100 = 60 crore

CSR spending in the year 2004 = $$\dfrac{5/3}{100}\times 100$$ = 1 crore.

Similarly, we can calculate for the remaining years. Tabulating the same data, (All the values are in crores)

From the table, we can see that the increase in CSR spending 2006 is more than 1.5 times as compared to previous year whereas for none of the other values this is true. Hence, option B is the correct answer. 

Total value of assets in the year 2004 = 100 crore

Total value of sales in the year 2004 = 0.60*100 = 60 crore

CSR spending in the year 2004 = $${5/3}{100}\times 100$$ = 1 crore.

Similarly, we can calculate for the remaining years. Tabulating the same data, (All the values are in crores) 

CSR/ Assets ratio for the year 2004 = $$\dfrac{1}{100}$$ = 0.01

CSR/ Assets ratio for the year 2005 = $$\dfrac{1.15}{110}$$ = 0.01045

CSR/ Assets ratio for the year 2006 = $$\dfrac{2}{125}$$ = 0.016

CSR/ Assets ratio for the year 2007 = $$\dfrac{2}{135}$$ = 0.0148

CSR/ Assets ratio for the year 2008 = $$\dfrac{2.5}{150}$$ = 0.0166

We can see that CSR/Asset ratio is maximum for the year 2008. Hence, option E is the correct answer.

Total value of assets in the year 2004 = 100 crore

Total value of sales in the year 2004 = 0.60*100 = 60 crore

CSR spending in the year 2004 = $$\dfrac{5/3}{100}\times 100$$ = 1 crore.

Similarly, we can calculate for the remaining years. Tabulating the same data, (All the values are in crores) 

From the table we can see that maximum spending on CSR activities in the period 2004 - 2009 = 3.16 crore $$\approx$$ 3 crore. Hence, option D is the correct answer. 

Total value of assets in the year 2004 = 100 crore

Total value of sales in the year 2004 = 0.60*100 = 60 crore

CSR spending in the year 2004 = $$\dfrac{5/3}{100}\times 100$$ = 1 crore.

Similarly, we can calculate for the remaining years. Tabulating the same data, (All the values are in crores) 

From the table, we can see that the CSR spending never decreased as compared to previous year. Hence, option E is the correct answer. 

Percentage of Ex-defense serviceman in level 1 = $$\dfrac{6}{52}\times 100$$ = 11.54 percent

Percentage of Ex-defense serviceman in level 2 = $$\dfrac{8}{65}\times 100$$ = 12.31 percent

Percentage of Ex-defense serviceman in level 3 = $$\dfrac{30}{210}\times 100$$ = 14.28 percent

Percentage of Ex-defense serviceman in level 4 = $$\dfrac{25}{130}\times 100$$ = 19.23 percent

Percentage of Ex-defense serviceman in level 5 = $$\dfrac{60}{330}\times 100$$ = 18.18 percent

We can see that in level 4 the Ex-Defence Servicemen are the highest in percentage terms. Hence, option D is the correct answer. 

From the bar graph we can see that actual staff strength is 130 whereas the staff requirements is 255. So, the company has to abolish 125 vacant seats. we can see that the company has to abolish nearly 50 percent of the total strength which is greater than any other remaining levels. Hence, option D is the correct answer.  

Percentage representation of Ex- policemen in level 1 = $$\dfrac{4}{52}\times 100$$ = 7.69 percent

Percentage representation of Ex- policemen in level 2 = $$\dfrac{4}{65}\times 100$$ = 6.15 percent

Percentage representation of Ex- policemen in level 3 = $$\dfrac{9}{210}\times 100$$ = 4.29 percent

Percentage representation of Ex- policemen in level 4 = $$\dfrac{7}{130}\times 100$$ = 5.38 percent

Percentage representation of Ex- policemen in level 5 = $$\dfrac{15}{330}\times 100$$ = 4.54 percent

We can see that in level 3 the Ex- policemen are the lowest in percentage terms. Hence, option C is the correct answer.