TISSNET 2016

Let the total number of students earlier = n

After 2 old students comes, total number of students = n + 2

Given that,

total number of chocolates = 200

So, earlier, chocolate for each students = 200 / n

When 2 students joins, chocolate foe each students = 200 / n + 2

According to Question,

(200 / n) - 5 = 200 / (n + 2)

(n + 2) (200 - 5 n) = 200 n

5 n^2 + 10 n - 400 = 0

5 n^2 + 50 n - 40 n - 400 = 0

5 n ( n + 10 ) - 40 ( n + 10 ) = 0

n = 8

Thus number of students earlier = 8

If rimi was born on Saturday.
Then Rima was born 13 days before.
So there is Sunday.
As 1 week has 7 days.
So 13 - 7 = 6
As rima was born 7 days before then there will be Saturday. ATQ we have 6 days left if you will deduct 6 days from Saturday so there will be Sunday And the date would be 19/2/2012

At end of the game each player holds = 32

Total money is 4×32=Rs. 128

Let Frank start with Rs. x

Then the total money other 3 have =Rs. (128−x)

Frank lost the first game. He gives Rs. (128−x) to the other 3 players.

Therefore, after the 1st game, money that Frank has

=x−(128−x)=2x−128

Total money other 3 players have =2(128−x)

In the second, third, and fourth games, the other 3 partners will lose, and each time, the loser doubles the amount of money that the others have.

i.e., after 2nd game, Frank money =2(2x−128)

i.e., after 3rd game, Frank money =4(2x−128)

i.e., after the 4th game, Frank money =8(2x−128)

At the start of the game, Frank started with 66rs.

He starts towards the west, walks 100 meters. Turns towards the north walk 100 meters. Turns towards the west and walks 50 meters. Hence Final position = North- west.

In T hours, the minute hand completes T laps. In the same amount of time, the hour hand completes T/12 laps.

The first time the minute and hour hands overlap, the minute hand would have completed 1 lap more than the hour hand. So we have T = T/12 + 1. This implies that the first overlap happens after T = 12/11 hours (~1:05 am). Similarly, the second time they overlap, the minute hand would have completed two more laps than the hour hand. So for N overlaps, we have T = T/12 + N.

Since we have 24 hours in a day, we can solve the above equation for N

24 = 24/12 + N
24 = 2 + N
N = 22

Thus, the hands of a clock overlap 22 times a day. Thus the hands of the clock overlap at 12:00, ~1:05, ~2:10, ~3:15, ~4:20, ~5:25, ~6:30, ~7:35, ~8:40, ~9:45, ~10:50. Note that there is no ~11:55. This becomes 12:00.

Hence they meet every 65 min

9% of total number of respondents surveyed = 3591

$$\Rightarrow$$ Total number of respondents surveyed= 39900

$$\therefore\ $$ Number of 3G Smart Phone users surveyed = 34% of 39900 = $$\frac{34}{100}\times39900$$ = 13566

A and B are alternately being increased and decreased.