TISSNET 2016

190000 people in the age group of 56-65 => 5.12% of total = 190000

number of people in the age bracket 26-35 in the city = 17.25% of total = 17.25 x 190000/5.12 = 640000

The prime numbers are 2,3,5,7,11,13,17,19,23,29, 31,37...

Three Consecutive Prime Numbers whose sum is 83 are 23,29,31

Reverse of largest number =13

Square = 169

The possibilities are 

Neena - Arnav - Deepali - Ananyaa

Neena - Ananyaa - Deepali - Arnav

Arnav - Deepali - Ananyaa - Neena

Ananyaa - Deepali - Arnav - Neena

The logic here is

W = 23, G = 7 $$\longrightarrow\ $$ 23 x 7 =161

U = 21, Q = 17 $$\longrightarrow\ $$ 21 x 17 = 357

N = 14, S = 19 $$\longrightarrow\ $$ 14 x 19 = 266

Similarly,

R = 18, M = 13 $$\longrightarrow\ $$ 18 x 13 = 234

$$\therefore\ $$The required number = 234

Hence, the correct answer is Option B

HCF of 6, 12 and 15 is 3, so Amrita can cut cubes of side 3 cm.

Total no. of cubes $$=\frac{6\times\ 12\times\ 15}{3^3}=40$$

Let there be 600kg of rice.

Each adult eats = 5kg

Each child eats = 3kg

!50 children eat =150 x 3 = 450 kg

Remaining rice = 150kg

Number of adults that can be fed = 150/5=30

Let the ratio of messages during day and night be x:y.

Let the charge of messages during the day be 100, so the charge of messages during the night will be 50.

Initial total bill=100*(x+y)

New total bill= 100*x + 50*y = 50*(2x+y)

Now, $$\frac{50\times\ \left(2x+y\right)}{100\times\ \left(x+y\right)}=\frac{80}{100}$$

$$10x+5y=8x+8y$$

x:y=3:2

Using the conditions given in the question, the path diagram is as given below.

Thus, I, J and K can only be reached from E.

Hence, the answer is option B.

Let the letters be numbered as A=1, B=2 ..... Z=26

D - A = 4 - 1 = 3

I - D = 9 - 4 = 5

P - I = 16 - 9 = 7

Y - P = 25 - 16 = 9

$$\therefore\ $$P should come in the place of '=' in the given series.

Hence, the correct answer is Option C

The logic here is

$$64=4^3$$

$$1000=10^3$$

$$4096=16^3$$  and

$$512=8^3$$

$$2744=14^3$$

$$8000=20^3$$

The difference is 6

Similarly,

$$216=6^3$$

$$1728=12^3$$

$$5832=18^3$$

$$\therefore\ $$The required number is 5832