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9Â years, 5Â months ago
9Â years, 5Â months ago
Let the price of Amul be X per litre and price for Sudha be Y per litre, and Z litre is removed and added
We further know that their price (in per litre) is same after the process.
So we get the equation.
{(130-Z)X +ZY}/(130-Z+Z) = {180-Z)Y +ZX}/(180-Z+Z)
Simplifying, we get
X - Z(X-Y)/130 = Y + Z(X-Y)/180
X-Y = Z(X-Y)/130 + Z(X-Y)/180
cancelling (X-Y), WE GET
1= Z/130 + Z/180
which gives the value of Z = 75.5 litres
1Â year, 4Â months ago
Why to take 130 and 180 in the denominator even though it's not mentioned they have same price per litre ?
7Â years, 10Â months ago
Hey guys as @Kunal Manchanda has wrote clear solution, I just thought it might help you to give a pdf for Formulas and tips on Mixtures and allegations.Â
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