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pedanaboina jhansi
CAT Preparation Community 10y ago
the average of the first nine integral multiples of 3 is
2
pedanaboina jhansi 10y ago
15
Pv Aaditya 10y ago
The sum of the series is 3*(1+2+3+...+9) = 3 * 9 * 10/2
Required average = (3*9*10/2) / 9 = 3 * 10/2 = 15
