RPF 16 Jan 2019

Total production of company :

X = 75 + 81 + 78 + 87 + 85 = 406

Y = 80 + 85 + 83 + 92 + 89 = 429

Z = 83 + 89 + 85 + 93 + 91 = 441

Thus, average production for the five years was minimum for company X.

=> Ans - (A)

Since, there are an equal number of male and female employees in the company, and also the average productivity is 81 calls per day which is equal to the number of calls attended by the males.

Thus, number of calls attended per day by a female employee will also equal to = 81

=> Ans - (B)

% of non defective bulbs = $$100-19=81\%\equiv2187$$

=> Number of defective products = $$19\%\equiv\frac{2187}{81}\times19$$

= $$27\times19=513$$

=> Ans - (C)

Sum of digits of 81815 = 8+1+8+1+5=23

Now, when 23 is divided by 9, => $$23=9\times2+5$$

Thus, remainder = 5

=> Ans - (B)

Given : $$x=0.675555....$$

=> $$100x=67.5555.....$$ ------------(i)

=> $$1000x=675.5555.....$$ ------------(ii)

Subtracting equation (i) from (ii), we get :

=> $$900x=675.5555-67.5555=608$$

=> $$x=\frac{608}{900}$$

=> Ans - (C)

Let total distance = $$2d$$ km

Using, time = distance/speed

=> $$\frac{d}{20}+\frac{d}{30}=8.5$$

=> $$\frac{30d+20d}{600}=8.5$$

=> $$5d=8.5\times60$$

=> $$d=8.5\times12=102$$

$$\therefore$$ Total distance of the entire journey = $$2\times102=204$$ km

=> Ans - (B)

Let ideal time taken = $$t$$ hours

Also, speed is inversely proportional to time.

=> $$\frac{20}{24}=\frac{t-\frac{9.5}{60}}{t+\frac{9.5}{60}}$$

=> $$5t+\frac{9.5}{12}=6t-\frac{9.5}{10}$$

=> $$6t-5t=\frac{9.5}{12}+\frac{9.5}{10}$$

=> $$t=\frac{47.5+57}{60}=\frac{104.5}{60}$$

$$\therefore$$ Distance = speed $$\times$$ time

= $$20\times(\frac{104.5}{60}+\frac{9.5}{60})$$

= $$\frac{114}{3}=38$$ km

=> Ans - (C)

Expression : $$((7^2)^3 \div 49^2) \times ([32 - 20] \div 4)$$

= $$7^{(6-4)}\times\frac{12}{4}$$

= $$49\times3=147$$

=> Ans - (D)

Average weight of first 4 bangles = 74 grams

=> Weight of first 4 bangles = $$74\times4=296$$ grams

Similarly, weight of remaining 6 bangles = $$75\times6=450$$ grams

$$\therefore$$ Average weight of the total bangles = $$\frac{296+450}{10}=74.6$$ grams

=> Ans - (B)

Average weight of 93 Notebooks in a box = 9.3 kg

=> Total weight = $$93\times9.3=864.9$$ kg

Let weight of new book = $$x$$ kg

=> New average = $$\frac{864.9+x}{94}=9.4$$

=> $$864.9+x=94\times9.4=883.6$$

=> $$x=883.6-864.9=18.7$$ kg

=> Ans - (A)