RPF 16 Jan 2019

Since, HCF X LCM = PRODUCT OF NUMBERS

LET THE OTHER NUMBER BE X.

SO,     21 X 63 = 21 * X

X = 63 (ANS)

$$166 - [8^2 - 7^2 + \sqrt{(72 - 64 \div 8[18 \times 18 \div 324])}]$$

HERE, WE WILL USE BODMAS RULE. Bracket, Of, Division, Multiplication, Addition and Subtraction. It explains the order of operations to solve an expression. 

$$166-[8^2 - 7^2 + \sqrt{(72 - 64 \div 8[18 \times 1/18])}]$$  { solving 18/324 = 1/18}

$$166-[8^2 - 7^2 + \sqrt{(72 - 64 \div 8[1])}]$$   { solving 18*1/18}

$$166-[8^2 - 7^2 + \sqrt{(72 - 64 \div 8[1])}]$$   {solving 64/8}

$$166-[8^2 - 7^2 + \sqrt{(72 - 8)}]$$   {solving 64/8}

$$166-[8^2 - 7^2 + \sqrt{(64)}]$$   {solving 72-8}

$$166-[8^2 - 7^2 + 8]$$   {solving sqrt64}

$$166-[64-49+8]$$   {solving 72-8}

$$166-[23]$$   {solving bracket}

$$166-23$$   

$$143$$  

By formula, SP = MP[1-D%/100}    S.P. = SELLING PRICE AND M.P. = MARKED PRICE AND C.P. = COST PRICE

SP = MP [1-10/100][1-20/100]

SP = MP x 9/10 X 4/5

SP = 36 MP/50

MP = SP x 50/36

MP = 1980 x 50/36 = 2750

CP  = MP/2 (GIVEN)

CP = RS. 2750/2 = RS. 1375

AMOUNT(A) = PRINCIPAL(P) + SIMPLE INTEREST(SI)

A = P + PRT/100

A = 8400 + 8400*11*5/100 = RS. 13020

AMOUNT REINVESTED = A/2 (GIVEN)

AMOUNT REINVESTED = 13020/2 = RS. 6510 

LET TOTAL SALARY BE S.

SALARY GIVEN TO :

VISUALLY CHALLENGED = 13S/100

ORPHANAGE = 12S/100

PHYSICALLY CHALLENGED = 14S/100

MEDICAL HELP = 16S/100

TOTAL SALARY GIVEN = 1S+12S+14S+16S/100 = 55S/100

LEFT AMOUNT  = 45S/100 = 19575 (GIVEN)

S = 43500

SO, AMOUNT DONATED TO VISUALLY CHALLENGED = 13 * 43500 / 100 = RS. 5655

LET THE AMOUNT WITH ANKIT, BABU , CHRISTO (C) AND DAVID (D) BE 5X,4X,3X AND 2X RESPECTIVELY.

SINCE C = 117+ D

3X = 117 + 2X

X = 117

SO, BABU SHARE = 4X = 17*4 = 468

LET THE LENGTH BE L AND BREADTH BE B OF THE FLOOR.

L = 1.25 B (GIVEN)

L*B = 320

SOLVING, BOTH THE EQUATIONS, WE GET

B = 16 AND L = 20

L + B = 36 M

LET THE THREE NUMBERS IN THE ORDER BE A,B AND C.

GIVEN :

A+B+C = 243          (1)

A/B = 2/3, SO 3A = 2B

AND B/C = 3/4, SO 4B = 3C

PUTTING VALUES OF B IN EQUATION 1, WE GET 

B = 81, A = 54 AND C= 108

SECOND NUMBER IS 81.

SELLING PRICE (S.P.) = 1710

C.P. = COST PRICE

PROFIT (P) = 14%

P% = SP-CP/CP * 100

P = S/C - 1

114/100 = S/C

C = 100S/114

C= 100 * 1710/114 = 1500

SO, THE ANSWER = 1500/2 = 750

LET THE COST PRICE AND SELLING PRICE OF THE ARTICLE BE C AND S RESPECTIVELY.

GAIN = 701-C

LOSS = C-365

GIVEN LOSS = 60/100 GAIN

C-365 = 0.6 (701-C)

ON SOLVING , WE GET

C = 491

SO, COST PRICE = RS. 491