RPF 10 Jan 2019 Slot 1

Marks obtained = 46 + 84 + 44 + 36 = 210

Maximum marks = 80 + 100 + 70 + 50 = 300

$$\therefore$$ Overall percentage obtained by him = $$\frac{210}{300}\times100=70\%$$

=> Ans - (B)

When a number is divided by 119 it leaves a remainder 15, let the number be = $$119 + 15 = 134$$

Now, when 134 is divided by 17, => $$134=17\times7+15$$

Thus, remainder = 15

=> Ans - (D)

Principal sum = Rs. 6800

Rate of interest = 8% and time period = 5 years

Simple interest = $$\frac{P\times R\times T}{100}$$

= $$\frac{6800\times8\times5}{100}=Rs.$$ $$2720$$

Thus, total amount after 5 years = $$Rs.$$ $$(6800+2720)=Rs.$$ $$9,520$$

$$\therefore$$ Remaining amount after half of the total amount is been invested in Share market = $$\frac{9520}{2}=Rs.$$ $$4,760$$

=> Ans - (C)

Expression : $$\frac{2}{5}(x) + \frac{3}{10}(x) - \frac{3}{5}(x) = 459$$

=> $$x\times(\frac{4+3-6}{10})=459$$

=> $$x=459\times\frac{10}{1}=4590$$

=> Ans - (D)

Let ideal time taken = $$t$$ hours

Also, speed is inversely proportional to time.

=> $$\frac{15}{20}=\frac{t-\frac{2.5}{60}}{t+\frac{2.5}{60}}$$

=> $$15t+\frac{2.5}{4}=20t-\frac{2.5}{3}$$

=> $$20t-15t=\frac{2.5}{4}+\frac{2.5}{3}$$

=> $$t=\frac{7.5+10}{60}=\frac{17.5}{60}$$

$$\therefore$$ Distance = speed $$\times$$ time

= $$15\times(\frac{17.5}{60}+\frac{2.5}{60})$$

= $$\frac{20}{4}=5$$ km

=> Ans - (A)

% of non defective bulbs = $$100-13=87\%\equiv4611$$

=> Number of defective products = $$13\%\equiv\frac{4611}{87}\times13$$

= $$53\times13=689$$

=> Ans - (C)

Expression : $$13.24 + 24.35 + 35.46 - 46.57 = 2\times?$$

=> $$2x=73.05-46.57$$

=> $$x=\frac{26.48}{2}=13.24$$

=> Ans - (A)

Number of trailing zeroes = $$\frac{243}{5}+\frac{243}{25}+\frac{243}{125}$$

= $$48+9+1=58$$     [Number will be round off to the lowest value]

=> Ans - (C)

Product of the 2 numbers = Product of L.C.M. and H.C.F.

= $$9167\times1=9167$$

=> Ans - (C)

Total sales of all the branches (in thousands) for the year 2010

 = 68 + 79 + 85 + 66 + 82 = 380

=> Average sales of all the branches (in thousands) for the year 2010 = $$\frac{380}{5}=76$$

=> Ans - (D)