RPF 10 Jan 2019

In given series BEH, MPS, JLP, QTW, DGJ

We can observe that the pattern followed is, In each term, First letter and second letter have two letters between them in alphabetical order & second and third letters have two letters between them. This pattern is observed in all terms except JLP. Hence, JLP doesn't belong to group.

Represent the information in diagram.

So, boy's mother will be sister in law for the lady.

So, the answer would be option d)Sister-in-law

So, the answer would be option a)1,2,3

In given list of letters, Q, L, J, N are consonants whereas letter A is a vowel. Hence, letter A doesn't belong to Group.

ABCD is the table and the glass piece is placed inside.

Side of glass = $$\sqrt{324}=18$$ cm

Width between glass and table = $$3$$ cm

=> Side of table = $$3+18+3=24$$ cm

=> Ans - (B)

Let ideal time taken = $$t$$ hours

Also, speed is inversely proportional to time.

=> $$\frac{10}{12}=\frac{t-\frac{6}{60}}{t+\frac{7}{60}}$$

=> $$10t+\frac{7}{6}=12t-\frac{6}{5}$$

=> $$12t-10t=\frac{7}{6}+\frac{6}{5}$$

=> $$t=\frac{35+36}{60}=\frac{71}{60}$$

$$\therefore$$ Distance = speed $$\times$$ time

= $$10\times(\frac{71}{60}+\frac{7}{60})$$

= $$\frac{78}{6}=13$$ km

=> Ans - (A)

If total salary is 100%, then % salary remaining after the donations = $$100-(16+12+13+14)=45\%$$

According to ques, $$45\%\equiv Rs.$$ $$20,925$$

Thus, amount donated to orphanage = $$12\%\equiv\frac{20925}{45}\times12$$

= $$465\times12=Rs.$$ $$5,580$$

=> Ans - (C)

Since, there are an equal number of male and female employees in the company, and also the average productivity is 75 calls per day which is equal to the number of calls attended by the males.

Thus, number of calls attended per day by a female employee will also equal to = 53

=> Ans - (C)

Let length of train = $$l$$ m and speed = $$s$$ m/s

Speed of train which takes 53 seconds to cross a bridge of length 288 m = $$s=\frac{288+l}{53}$$ -----------(i)

Also, $$s=\frac{l}{17}$$ --------------(ii)

Substituting value of $$s$$ from equation (ii) in (i), we get :

=> $$\frac{l}{17}=\frac{288+l}{53}$$

=> $$53l=(288\times17)+17l$$

=> $$53l-17l=36l=288\times17$$

=> $$l=\frac{288\times17}{36}=136$$

$$\therefore$$ Length of train = 136 m

=> Ans - (D)