RPF 10 Jan 2019

Let number of 3 rupees, 4 rupees and 5 rupees respectively be $$11x,13x$$ and $$12x$$

Total amount = $$(3\times11x)+(4\times13x)+(5\times12x)=725$$

=> $$33x+52x+60x=725$$

=> $$x=\frac{725}{145}=5$$

$$\therefore$$ Number of 3 rupees coins = $$11\times5=55$$

=> Ans - (B)

Rate of interest = 4% and time period = 2 years

Let principal sum = Rs. $$P$$

Also, difference between compound interest and simple interest for 2 years = $$P(\frac{r}{100})^2$$

=> $$P(\frac{4}{100})^2=28$$

=> $$P=28\times\frac{10000}{16}$$

=> $$P=Rs.$$ $$17,500$$

=> Ans - (A)

The amount gets doubled in 3 years.

In case of compound interest, the amount will become $$2^n$$ times in $$3n$$ years

=> Final amount = $$8=(2)^3$$

Thus, after $$3\times3=9$$ years, amount will become 8 times.

=> Ans - (C)

Let salary of Ram, Raj and Rio be $$5x,7x$$ and $$9x$$ respectively.

According to ques, => $$9x-5x=280$$

=> $$x=\frac{280}{4}=70$$

$$\therefore$$ Raj's salary = $$7\times70=Rs.$$ $$490$$

=> Ans - (A)

Total sales of all the branches (in thousands) for the year 2010

= 56 + 78 + 68 + 56 + 82 = 340

=> Average sales of all the branches (in thousands) for the year 2010 = $$\frac{340}{5}=68$$

=> Ans - (C)

Ratio of time taken = 17 : 14

Since, both are covering the same distance, and speed is inversely proportional to time.

Thus, ratio of their speeds = 14 : 17

=> Ans - (A)

Let share of each kid be $$a,b,c,d$$ respectively.

Then according to ques, => $$a=2b=3c=4d=k$$

=> $$a=k$$ , $$b=\frac{k}{2}$$ , $$c=\frac{k}{3}$$ , $$d=\frac{k}{4}$$

Thus, total = $$a+b+c+d=250$$

=> $$k+\frac{k}{2}+\frac{k}{3}+\frac{k}{4}=250$$

=> $$k\times(\frac{12+6+4+3}{12})=250$$

=> $$k=250\times\frac{12}{25}=120$$

$$\therefore$$ Number of gifts received by the 2nd kid = $$b=\frac{k}{2}$$

= $$\frac{120}{2}=60$$

=> Ans - (D)

When a number is divided by 36 it leaves a remainder 7, let the number be = $$36 + 7 = 43$$

Now, when 43 is divided by 9, => $$43=9\times4+7$$

Thus, remainder = 7

=> Ans - (A)

Marks obtained = 71 + 81 + 51 + 31 = 234

Maximum marks = 80 + 100 + 70 + 50 = 300

$$\therefore$$ Overall percentage obtained by him = $$\frac{234}{300}\times100=78\%$$

=> Ans - (D)

Selling price = Rs. 1089 and profit % = 12.5%

=> Cost price = $$\frac{1089}{(100+12.5)}\times100$$

= $$9.68\times100=Rs.$$ $$968$$

$$\therefore$$ Amount which is equal to half of the cost price of the product = $$\frac{968}{2}=Rs.$$ $$484$$

=> Ans - (B)