Sachin shared 250 gifts among 4 kids. The share of the first kid, twice the share of second kid, thrice the share of third kid and four times the share of fourth kid are all equal. Find the number of gifts received by 2nd kid.

Let share of each kid be $$a,b,c,d$$ respectively.

Then according to ques, => $$a=2b=3c=4d=k$$

=> $$a=k$$ , $$b=\frac{k}{2}$$ , $$c=\frac{k}{3}$$ , $$d=\frac{k}{4}$$

Thus, total = $$a+b+c+d=250$$

=> $$k+\frac{k}{2}+\frac{k}{3}+\frac{k}{4}=250$$

=> $$k\times(\frac{12+6+4+3}{12})=250$$

=> $$k=250\times\frac{12}{25}=120$$

$$\therefore$$ Number of gifts received by the 2nd kid = $$b=\frac{k}{2}$$

= $$\frac{120}{2}=60$$

=> Ans - (D)