Production of iron in blast furnace follows the following equation
Fe$$_3$$O$$_4$$(s) + 4CO(g) $$\rightarrow$$ 3Fe(l) + 4CO$$_2$$(g)
when 4.640 kg of Fe$$_3$$O$$_4$$ and 2.520 kg of CO are allowed to react then the amount of iron (in g) produced is:
[Given: Molar Atomic mass (g mol$$^{-1}$$): Fe = 56, O = 16, C = 12]




