
(a) The diagram above contains 13 boxes. The numbers in the second and the twelfth boxes are respectively 175 and 70. Fill up the boxes with natural numbers such that
(i) the sum of all numbers in all 13 boxes is 2015,
(ii) the sum of the numbers in any three consecutive boxes is always the same.
The solution must contain the steps how you arrive at the numbers.
(b) If x, y, z are real and unequal numbers, prove that $$2015x^{2}+2015y^{2}+6z^{2} > 2(2012xy+3yz+3zx)$$.
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