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If $$(x+y+z)^3 = (y+z-x)^3+(z+x-y)^3+(x+y-z)^3+kxyz$$, find the numerical value of k. Deduce the following result. If $$a=2015, b=2014, c= \frac{1}{2014}$$ Prove that $$(a+b+c)^{3} -(a+b-c)^{3}-(b+c-a)^{3} -(c+a-b)^{3}-23abc = 2015$$
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