NICL (GIC) Administrative Officer Finance 2013 Exam Question paper

A multi processor (having 2 or more than 2 processing units) is a software that accepts user ideas. manipulates and recognises them in user specified ways and then produces a refined model of those thoughts.

=> Ans - (C)

For each girl to get the same number of bags and eyeliners, we need to find H.C.F. of 2923 and 3239

=> $$2923 = 37 \times 79$$

and $$3239 = 41 \times 79$$

=> H.C.F = 79

=> Ans - (B)

Expression : $$5^{71} + 5^{72} + 5^{73}$$

= $$5^{71} (1 + 5 + 5^2) = 5^{71} \times 31$$

= $$5^{70} \times 155$$

Clearly, above expression is easily divisible by 155.

=> Ans - (C)

The average 8 numbers is A

=> Sum of 8 numbers = 8A

Let average of first four of these is B

=> Sum of first four = 4B

Average of remaining four = C

=> Sum of last 4 = 4C

Also, sum of first 4 numbers + Sum of last 4 numbers = Sum of all the 8 numbers

=> $$4B + 4C = 8A$$

Dividing both sides by 4, we get :

=> $$2A = B + C$$

Marked price = Rs. 400

Selling price = Rs. 360

=> Discount % = $$\frac{400 - 360}{400} \times 100$$

= $$\frac{40}{4} = 10 \%$$

Given : 30% of (x - y) = 20% of (x + y)

=> $$\frac{30}{100} \times (x - y) = \frac{20}{100} \times (x + y)$$

=> $$3x - 3y = 2x + 2y$$

=> $$x = 2y + 3y = 5y$$

=> $$\frac{y}{x} = \frac{1}{5}$$

$$\therefore$$ Required % = $$\frac{1}{5} \times 100 = 20 \%$$

First five multiples of 5 = 5,10,15,20,25

=> Sum = 5+10+15+20+25 = 75

$$\therefore$$ Required average = $$\frac{75}{5}$$

= 15

Length of train = 450 m

Speed of train = 65 km/hr and speed of girl = 5 km/hr

Since, they are moving in the same direction, relative speed = 65 - 5 = 60 km/hr

= $$60 \times \frac{5}{18} = \frac{50}{3}$$ m/s

Let time taken = $$t$$ sec

=> $$t = \frac{450}{\frac{50}{3}}$$

=> $$t = 450 \times \frac{3}{50}$$

=> $$t = 9 \times 3 = 27$$ sec

Job monitoring or job scheduling is the control of the jobs running within a system.

=> Ans - (A)

REASONING ABILITY