Question 36

If 30% of (x - y) = 20% of (x + y), then what percent of x is y?

Solution

Given : 30% of (x - y) = 20% of (x + y)

=> $$\frac{30}{100} \times (x - y) = \frac{20}{100} \times (x + y)$$

=> $$3x - 3y = 2x + 2y$$

=> $$x = 2y + 3y = 5y$$

=> $$\frac{y}{x} = \frac{1}{5}$$

$$\therefore$$ Required % = $$\frac{1}{5} \times 100 = 20 \%$$

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