Sign in
Please select an account to continue using cracku.in
↓ →
The average of 8 numbers is A and the average of four of these is B. If the average of remaining four is C, then
The average 8 numbers is A
=> Sum of 8 numbers = 8A
Let average of first four of these is B
=> Sum of first four = 4B
Average of remaining four = C
=> Sum of last 4 = 4C
Also, sum of first 4 numbers + Sum of last 4 numbers = Sum of all the 8 numbers
=> $$4B + 4C = 8A$$
Dividing both sides by 4, we get :
=> $$2A = B + C$$
Was this solution helpful?
Create a FREE account and get:
Book Free CAT Mentorship
Get personalized CAT strategy from a 99%iler
500+ students mentored
OTP Verification
Enter the 6-digit code sent to your phone
Booking Summary
Enter OTP
Didn't receive the OTP?
Start your IIM journey with the right preparation and crack CAT 2026.
Educational materials for CAT preparation
Ask our AI anything
AI can make mistakes. Please verify important information.
AI can make mistakes. Please verify important information.
91- 6303239042
