The average of 8 numbers is A and the average of four of these is B. If the average of remaining four is C, then
The average 8 numbers is A
=> Sum of 8 numbers = 8A
Let average of first four of these is B
=> Sum of first four = 4B
Average of remaining four = C
=> Sum of last 4 = 4C
Also, sum of first 4 numbers + Sum of last 4 numbers = Sum of all the 8 numbers
=> $$4B + 4C = 8A$$
Dividing both sides by 4, we getย :
=> $$2A = B + C$$
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