MAT 2012 Question Paper

The ratio of the number of cars sold of model A in 2010 to the number of cars sold of model C in 2011 is given by,

= 21% of 2222 : 26% of 2884

= 3 x 1111 : 26 x 206 

= 0.62 : 1 

Hence, option C is the correct answer.

Increase in sales of model D from 2010 to 2011,

= 16% of 2884 - 16% of 2222

= 16% of 662

= 105.92

Increase in sales of model C from 2010 to 2011,

= 26% of 2884 - 22% of 2222

= 749.84 - 488.84 

= 261

Increase in sales of model C is more than sales of model D from 2010 to 2011. 

Required percentage = $$\frac{261 - 105.92}{261} \times 100 = \frac{155.08}{261} \times 100 = 59$$%

Hence, option C is the correct answer.

Total percentage increase from 2010 to 2011,

= $$\frac{2884 - 2222}{2222} \times 100 = 29.79$$%

Percentage increase in sales of A,

= $$\frac{0.27 \times 2884 - 0.21 \times 2222}{0.21 \times 2222} \times 100 = 66.87$$%

Percentage of increase in sales of B,

= $$\frac{0.25 \times 2884 - 0.25 \times 2222}{0.25 \times 2222} \times 100 = 29.79$$%

Percentage of increase in sales of C,

= $$\frac{0.26 \times 2884 - 0.22 \times 2222}{0.22 \times 2222} \times 100 = 53.33$$%

Percentage of increase in sales of D,

= $$\frac{0.16 \times 2884 - 0.16 \times 2222}{0.16 \times 2222} \times 100 = 29.79$$%

Percentage of increase in sales of E,

= $$\frac{0.08 \times 2884 - 0.12 \times 2222}{0.12 \times 2222} \times 100 =$$ Some negative value 

Percentage of increase in sales of F,

= $$\frac{0.06 \times 2884 - 0.04 \times 2222}{0.04 \times 2222} \times 100 = 94.68$$%

Three models i.e A, C, F have registered higher percentage increase in sales individually.

Hence, option B is the correct answer.

Two highest selling models in 2011 = (27% + 26%) of 2884 

Two lowest selling models in 2010  = (8% + 6%) of 2884

Their ratio = (27% + 26%) of 2884 : (8% + 6%) of 2884

= 53% of 2884 : 14% of 2884

= 53 : 14 

= 4 : 1 (approx)

Hence, option D is the correct answer.

Adult females below the age of 50 in the year 1990,

53% of 16965.2 = 8991.556 = 8992 (approx)

Adult females below the age of 50 in the year 2000,

48% of 22147.2 = 10630.656 = 10631 (approx)

Ratio = 8992 : 10631

= 1 : 1.18

Hence, option C is the correct answer.

Adult females above the age of 50 in 1990 = 53% of 3474.8 = 1841.644

Total allowance given = 1842 x 24000 = 4,42,08,000

Adult females above the age of 50 in 2000 = 48% of 8612.8 = 4134

Total allowance given = 4134 x 30000 = 12,40,20,000

$$\therefore$$ Percentage increase in annual allowance from 1990 to 2000,

= $$\frac{12,40,20,000 - 4,42,08,000}{4,42,08,000} \times 100$$

= $$\frac{79812}{44208} \times 100$$

= $$180$$%

Hence, option D is the correct answer.

Total adult illiterates in 1990 = 12264

Total adult females below 50 in 2000 = 48% of 22147.2 = 10631

Ratio = 12264 : 10631

= 1.15 : 1

Hence, option B is the correct answer.

Total number of adult literates in 1990 = 8176

Total number of adult literates in 2000 = 23760

Percentage increase = $$\frac{23760 - 8176}{8176} \times 100$$

= $$\frac{1558400}{8176} = 190.60 = 191$$% (approx)

Hence, option B is the correct answer.

Total adult literates in 1990 = 8176

Total expense on education in 1990 = 1200 x 8176 = 9811200

Total adult literates in 2000 = 23760

Total expense on education in 2000 = 125% of 1200 x 23760 = 35640000

Percentage increase =  $$\frac{35640000 - 9811200}{9811200} \times 100$$

= $$\frac{25828800}{98112} = 263$$%

Hence, option B is the correct answer.