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The adult population of a town in 1990 was 20440 people of which 53% were females while 60% were illiterates. Of these, the number above the age of 50 in that year was 17%. In the 2000 Census, it was found that adult population has reached 30760, 48% of them being females. Of the total adult population in 2000, 72% were below the age of 50 and total illiterates were 7000. Assume uniform pattern of age distribution amongst males and females.
Total number of adult literates in 1990 = 8176
Total number of adult literates in 2000 = 23760
Percentage increase = $$\frac{23760 - 8176}{8176} \times 100$$
= $$\frac{1558400}{8176} = 190.60 = 191$$% (approx)
Hence, option B is the correct answer.
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